This puts the pixie spells working about 15-35% of the time, depending on the saving throw in question. He is also immune to the pixies’ polymorph, due to the spell not working against shapeshifters.

Strahd doesn’t have any immunities innately, but he has great base stats and has proficiency in charisma, dexterity, and wisdom saving throws. It’s not exactly an unreasonable scenario. For this case, let’s say that legendary resistance was used by Strahd once, and let’s say the pixies go before Strahd’s next turn. We have to make a few assumptions to start off. If an 11th-level druid, based on the question asked in the community, did this against the mighty Count Zarovich, what would happen? Also, the pixies don’t have a very challenging DC, only checking in at 12. The druid can fail a check, and the shenanigans end. Their dexterity bonus is pretty good, so they likely get to act in a timely fashion.

However, you trade a single 4th-level spell slot for each one of the following: confusion, dancing lights, detect evil and good, detect thoughts, dispel magic, fly, phantasmal force, polymorph, and sleep. The pixies follow your command, which costs you no action, and have their own initiative. Pixies are a CR 1/8 creature, mainly because they deal 0 damage and are fragile. It’s not any secret conjure woodland beings is broken. Anyway, I thought I would examine what casting conjure woodland beings against Strahd might look like, based on the question being asked. From what I understand, characters are meant to be 9th when they engage Strahd, but obviously this varied for whatever reason. The person confirmed the character was high enough level to cast a 6th. However, the hilariously broken conjure woodland beings allows you to summon eight pixies at 4th-level, or sixteen pixies at 6th-level, the same level slot you’d need to cast conjure fey in the first place. I mean, a fey mammoth is always a good choice if you are going to stick with that particular spell. When you cast this spell using certain higher-level spell slots, you choose one of the summoning options above, and more creatures appear: twice as many with a 6th-level slot and three times as many with an 8th-level slot.In an online community the other day, it was asked what a druid could summon with conjure fey that was “worth a crap” against Strahd von Zarovich, Count of Barovia. You can see some sample creatures below.Īt Higher Levels. If you don’t issue any commands to them, they defend themselves from hostile creatures, but otherwise take no actions. They obey any verbal commands that you issue to them (no action required by you). Roll initiative for the summoned creatures as a group, which have their own turns. The summoned creatures are friendly to you and your companions.

Eight fey creatures of challenge rating 1/4 or lowerĪ summoned creature disappears when it drops to 0 hit points or when the spell ends.

Four fey creatures of challenge rating 1/2 or lower.

Two fey creatures of challenge rating 1 or lower.

One fey creature of challenge rating 2 or lower.

Choose one of the following options for what appears: You summon fey creatures that appear in unoccupied spaces that you can see within range. One holly berry per creature summoned Class Druid Ranger Spell Description Concentration, up to 1 hour Components V S M Materials Required

Conjure woodland beings 5e